Theorem : The sum of the angles of a triangle is 180°
Given A △ABC
To Prove ∠1 + ∠2 + ∠3 = 180°
Construction Through A, draw a line DE parallel to BC.
Proof DE ॥ BC and AB is the transversal.
∴ ∠1 = ∠4 (Alt. Int. angle) ............ (i)
Again, DE ॥ BC and AC is the transversal.
∴ ∠2 = ∠5 (Alt. Int. angle) ............ (ii)
On adding the corresponding sides of (i) and (ii)
∴ ∠1 + ∠2 = ∠4 + ∠5
On adding ∠3 on both sides
So, ∠1 + ∠2 + ∠3 = ∠4 + ∠5 + ∠3
But, ∠4 + ∠5 + ∠3 = ∠ DAE = 180°
( ∵ ∠DAE is a straight angle)
∴ ∠1 + ∠2 + ∠3 = 180°
Hence, the sum of the angles of a triangle is 180° .
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